Ammonia

Symmetry

In this section we are going to look at different isomers for NH3 and the effect of symmetry on the structures, energies and optimisation time. In this section we will be useing a 6-31G basis set and the B3LYP method.
  • generate an NH3 molecule in gaussview and optimise it (save your output file)
    • determine the symmetry of your molecule by looking at the calculation summary in Gaussview, save a snapshot of the summary window and include it in your report.
    • the symmetry should be C3v
  • generate another NH3 molecule in gaussview and make one bond longer than the others by setting it to 1.01Å, and under the general tab, tick ignore symmetry and then run the optimisation
    • save a snapshot of the summary window and include it in your report.
    • the symmetry should be C1
  • now use the file nh3_b3lyp_d3h.txt and run another optimization. First, copy the contents of this file to one in your directory called nh3_b3lyp_d3h.com and open it in Gaussview. You will see an extra pink "atom", this is called a dummy atom, and I have used it to help define the restricted symmetry of this molecule. Do not make any changes to this file, just run it.
    • save a snapshot of the summary window and include it in your report.
    • the symmetry should be D3h
    • optional If you are interested in knowing how the symmetry is restricted, look at the contents of the input .com file in conjunction with the section on "z-matricies" in the "Exploring Chemistry with Electronic Structure Methods" book.
  • now would be a good time to review the difference between the symmetry groups C1, C3v, and D3h. If you are taking the symmetry and spectroscopy course you will also know (or be finding out shortly!) that these symmetry groups are related to one-another, C1 is a sub-group of C3v which is a sub-group of D3h.
  • Look over the three optimisation jobs and answer the following questions in your report:
    • has the symmetry made any difference to the final structure obtained?
    • has the symmetry made any difference to the time it took to optimise the geometry?
    • what implication does symmetry have for the time it takes to do a calculation?
    • can a molecule "break symmetry" during an optimisation?
    • what implications does this have if you enter a high symmetry structure to optimise?
    • which is the lowest energy geometry?
    • what is the energy in kJ/mol of the other two isomers above the energy of the lowest energy structure? Hint: take ΔE=E(high energy)-E(low energy), the energy units are reported in atomic units so you will need to convert the energy difference to kJ/mol.
    • is the energy differences between these structures significant? Explain why.

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